To sort an array of strings in JavaScript, you can use the sort() method, which sorts the elements of an array in place and returns the sorted array. Here is an example:

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const fruits = ['banana', 'apple', 'orange', 'mango'];
fruits.sort();
console.log(fruits); // Output: ['apple', 'banana', 'mango', 'orange']

In this example, the fruits array is sorted alphabetically using the sort() method. By default, the sort() method sorts the elements in ascending order based on their Unicode code points. If you want to sort the elements in descending order, you can use the reverse() method after sorting, like this:

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const fruits = ['banana', 'apple', 'orange', 'mango'];
fruits.sort().reverse();
console.log(fruits); // Output: ['orange', 'mango', 'banana', 'apple']

This code first sorts the fruits array using the sort() method, then reverses the sorted array using the reverse() method, giving us a descending order.

To sort a JavaScript array, you can use the sort() method. This method sorts the elements of an array in place, meaning it changes the original array. The default sort order is in ascending order, which is suitable for sorting strings. For sorting numbers, you need to provide a compare function.

Here's an example of sorting a simple array of numbers in ascending order:

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let numbers = [10, 5, 8, 20, 3];
numbers.sort((a, b) => a - b);
console.log(numbers); // Output: [3, 5, 8, 10, 20]

In the above example, the sort() method sorts the array in ascending order of values a - b. If you want to sort the array in descending order, you can reverse the arguments of a and b:

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let numbers = [10, 5, 8, 20, 3];
numbers.sort((a, b) => b - a);
console.log(numbers); // Output: [20, 10, 8, 5, 3]

Note that the sort() method sorts the array in place and returns the sorted array.

Counting Sort is a sorting algorithm that operates on an array or list of integers. It works by counting the number of occurrences of each unique element in the list, and then using the counts to reposition the elements in order.

Here's an example of how Counting Sort would work for an array of integers:

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const countingSort = arr => {
  const max = Math.max(...arr);
  const counts = new Array(max + 1).fill(0);
  const sortedArr = [];

  arr.forEach(num => {
    counts[num]++;
  });

  counts.forEach((count, i) => {
    for (let j = 0; j < count; j++) {
      sortedArr.push(i);
    }
  });

  return sortedArr;
};

console.log(countingSort([3, 2, 1, 4])) // Output: [1, 2, 3, 4]

First, we find the maximum value in the array to determine the size of the counting array. Then, we fill the counting array with zeros and iterate through the input array, incrementing the corresponding count for each number. We then iterate through the counting array, adding each number in the right count to the sorted array. Finally, we return the sorted array.

Counting Sort has a time complexity of O(n+k), where n is the number of elements in the input array and k is the range of input. However, it has a space complexity of O(k), which can be prohibitively large for some inputs.