Identifier related coding questions - SheCodes Athena - AI | SheCodes

Identifier related coding questions

👩‍💻 Technical question

what is "Identifier has already been declared" ?

🤖 SheCodes Athena says:

Answered in 3.53 seconds

This error message typically occurs when you try to declare a variable or function with a name that has already been used in the same scope. In other words, you are trying to assign a value or define something using a name that is already being used elsewhere in your code.

Here's an example in JavaScript:

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let x = 10; let x = 20; // Error: Identifier 'x' has already been declared console.log(x);

In this example, we first declare a variable x and assign it a value of 10. Then, we try to declare another variable x with a different value of 20. This will result in an error because x has already been declared in the same scope.

To fix this error, you should use a different name for the variable or function, or remove the duplicate declaration if it's not needed. For example:

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let x = 10; let y = 20; console.log(x + y);

In the corrected code above, we use the variable name y instead of x to avoid the "Identifier has already been declared" error.

👩‍💻 Technical question

what is key in JS?

🤖 SheCodes Athena says:

Answered in 3.23 seconds

In JavaScript, a key refers to a unique identifier used to access values in an object. An object in JavaScript is a collection of key-value pairs, where the key is the identifier and the value is the associated data. Keys are used to access and manipulate the values stored in the object.

Here's an example of an object in JavaScript with keys:

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let person = { name: 'John', age: 25, occupation: 'Engineer' };

In this example, the keys are name, age, and occupation. These keys can be used to access the corresponding values:

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console.log(person.name); // Output: John console.log(person.age); // Output: 25 console.log(person.occupation); // Output: Engineer

You can also use keys to modify or add new values to an object:

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person.age = 26; person.city = 'New York'; console.log(person.age); // Output: 26 console.log(person.city); // Output: New York

Remember that keys in JavaScript are case-sensitive, so name is different from Name.

👩‍💻 What is different with this coe? : const person = { name : "Jana", age : 37 }; for ( let key in person) console.log(key, person[key]);

🤖 SheCodes Athena says:

Answered in 4.44 seconds

The code you provided creates an object named person with two properties: name and age. Here's a breakdown of what the code does:

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const person = { name: "Jana", age: 37 };

This code declares a constant variable person and assigns it an object with the properties name and age. The name property has the value "Jana", and the age property has the value 37. The const keyword ensures that the person variable cannot be reassigned to a different object.

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for (let key in person) { console.log(key, person[key]); }

This code uses a for...in loop to iterate over each key in the person object. The key variable represents each key in the loop, and person[key] accesses the corresponding value for that key.

During each iteration of the loop, the code logs the key and person[key] to the console. This means that it will print the key-value pairs of the person object:

Output:

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name Jana age 37

The output shows the keys (name and age) followed by the corresponding values ("Jana" and 37).

👩‍💻 Technical question

How to avoid case sensitive in java script

🤖 SheCodes Athena says:

Answered in 12.28 seconds

JavaScript is a case-sensitive language. To avoid case-sensitive errors, use the same case for all references to the same identifier. For example, userName and username are not the same in JavaScript.

In order to avoid confusion and potential errors, you can use the toUpperCase() or toLowerCase() methods which both take a string as argument and convert it to upper or lower case, respectively. For example:

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let myString = "Banana"; let newString = myString.toUpperCase(); console.log(newString); // Outputs: BANANA

👩‍💻 Technical question

in Javascript could you please add a identifier"enfant" to THE CHILD CLASS "search-section no-border" and then add a css to the class enfant : display:none;

🤖 SheCodes Athena says:

Answered in 7.48 seconds
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var childClass = document.querySelector('.search-section.no-border'); childClass.classList.add('enfant'); document.querySelector('.enfant').style.display = 'none';

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