2d array related coding questions - SheCodes Athena - AI | SheCodes

2d array related coding questions

👩‍💻 Technical question

Asked 2 years ago in C++ by Brenna

how to clear a 2d array c++

🤖 SheCodes Athena says:

Answered in 3.07 seconds

To clear a 2D array in C++, you can use the nested loops to iterate through each element of the array and set the values to 0 or any other default value.

Here is an example code snippet in C++ to clear a 2D array:

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int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}; // Clearing the array for(int i = 0; i < 3; i++) { for(int j = 0; j < 3; j++) { arr[i][j] = 0; // Set the value to 0 } }

In the above example, we have initialized a 2D array of 3x3 and then used two nested loops to set each element to 0. You can replace 0 with any other default value you want to set the array to.

👩‍💻 Technical question

Asked 2 years ago in C++ by Brenna

how to make a 2D array an argument of a function in C++

🤖 SheCodes Athena says:

Answered in 2.43 seconds

To make a 2D array an argument of a function in C++, you can declare the function with the array parameter using square brackets for both dimensions.

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void myFunction(int myArray[][3]) { // function body here }

In this example, myFunction() takes a 2D integer array as an argument. The size of the second dimension must be specified, while the size of the first dimension can be left empty or specified. In this case, the second dimension has a size of 3.

Here's an example of calling this function with a 2D array argument:

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int main() { int array2D[2][3] = {{1,2,3}, {4,5,6}}; myFunction(array2D); return 0; }

In this example, main() declares a 2D integer array called array2D, which is then passed as an argument to myFunction(). The function can then access or modify the elements of the array as needed.

👩‍💻 HTML, CSS and JavaScript Code instructions

Asked 2 years ago in C++ by Brenna

C++ print out a 2D array matrix style

🤖 SheCodes Athena says:

Answered in 2.48 seconds
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#include <iostream> using namespace std; int main() { int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}; for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { cout << arr[i][j] << " "; } cout << endl; } return 0; }

Explanation:

  • First, we define a 2D array arr with 3 rows and 3 columns.
  • Then, we use two for loops to iterate over all the elements in the array.
  • The outer for loop iterates over the rows (i) and the inner for loop iterates over the columns (j).
  • We use the cout statement to print out each element in a matrix style, with a space between each element and a newline character after each row.

👩‍💻 Technical question

Asked 2 years ago in C++ by Brenna

C++. How to do breadth first search on a 2D array

🤖 SheCodes Athena says:

Answered in 9.15 seconds

To perform a breadth-first search on a 2D array you can use a queue to store the elements to visit. Here is an example code in C++ to perform a BFS on a 2D array.

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#include <iostream> #include <queue> using namespace std; void bfs(int **arr, int rows, int cols, int start_row, int start_col) { // create a 2D boolean array to keep track of visited elements bool **visited = new bool*[rows]; for (int i = 0; i < rows; i++) { visited[i] = new bool[cols]; for (int j = 0; j < cols; j++) { visited[i][j] = false; } } // create a queue to store the elements to visit queue<pair<int, int>> q; // mark the starting element as visited and add it to the queue visited[start_row][start_col] = true; q.push(make_pair(start_row, start_col)); // define the neighbors of an element int dr[] = {-1, 1, 0, 0}; int dc[] = {0, 0, -1, 1}; // BFS loop while (!q.empty()) { // get the front element from the queue pair<int, int> curr = q.front(); q.pop(); int r = curr.first; int c = curr.second; cout << arr[r][c] << " "; // visit the neighbors of the front element for (int i = 0; i < 4; i++) { int nr = r + dr[i]; int nc = c + dc[i]; // check if the neighbor is within the array bounds and not visited if (nr >= 0 && nr < rows && nc >= 0 && nc < cols && !visited[nr][nc]) { visited[nr][nc] = true; q.push(make_pair(nr, nc)); } } } // free the memory used by the boolean array for (int i = 0; i < rows; i++) { delete[] visited[i]; } delete[] visited; } int main() { // example 2D array int rows = 3; int cols = 4; int **arr = new int*[rows]; for (int i = 0; i < rows; i++) { arr[i] = new int[cols]; for (int j = 0; j < cols; j++) { arr[i][j] = i * cols + j; } } // perform BFS on the array starting from element (1, 2) bfs(arr, rows, cols, 1, 2); // free the memory used by the 2D array for (int i = 0; i < rows; i++) { delete[] arr[i]; } delete[] arr; return 0; }

In this example, the bfs function takes the 2D array arr, the number of rows rows and columns cols of the array, and the starting element start_row and start_col as arguments. It creates a 2D boolean array visited to keep track of visited elements, initializes a queue q with the starting element, and starts a BFS loop. For each element visited, it prints its value and checks its neighbors. If a neighbor is within the array bounds and has not been visited, it is added to the queue and marked as visited. When the queue is empty, the function returns. Finally, the memory allocated for the boolean array and the 2D array is freed.

👩‍💻 Technical question

Asked 2 years ago in C++ by Brenna

C++. How to do depth first search on a 2D array

🤖 SheCodes Athena says:

Answered in 6.19 seconds

To perform a Depth First Search (DFS) on a 2D array in C++, you can use recursion.

Here is some sample code to perform a DFS on a 2D array:

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const int ROW = 3; const int COL = 3; // Helper function to perform a DFS on a 2D array void dfs(int arr[][COL], bool visited[][COL], int row, int col) { // Check if current cell is inside the boundaries of the array if (row < 0 || row >= ROW || col < 0 || col >= COL) { return; } // Check if current cell has been visited or its value is 0 if (visited[row][col] || arr[row][col] == 0) { return; } // Mark current cell as visited visited[row][col] = true; cout << arr[row][col] << " "; // Visit all neighbors dfs(arr, visited, row - 1, col); // up dfs(arr, visited, row + 1, col); // down dfs(arr, visited, row, col - 1); // left dfs(arr, visited, row, col + 1); // right } int main() { int arr[ROW][COL] = { {1, 0, 1}, {0, 1, 0}, {1, 0, 1} }; bool visited[ROW][COL]; // Initialize all cells as not visited memset(visited, false, sizeof(visited)); // Perform DFS on all unvisited cells for (int i = 0; i < ROW; i++) { for (int j = 0; j < COL; j++) { if (!visited[i][j] && arr[i][j] == 1) { dfs(arr, visited, i, j); } } } return 0; }

This code will run a DFS on a 2D array containing 1s and 0s, where 1s represent cells that should be visited and 0s represent cells that should be ignored.

The code initializes all cells as unvisited and loops through all cells in the array, calling the dfs function on each unvisited cell with a value of 1. During the DFS, the code recursively visits all neighboring cells with a value of 1 and marks them as visited, outputting their values as it goes.

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