Figure 1: Frequencies of genotypes AA, Aa and aa
p + q must equal 1.
What is Hardy-Weinberg Equilibrium?
Hardy-Weinberg equilibrium is a theorem that states that the
allele and genotype frequencies will remain
constant from generation to generation in the absence of other
evolutionary influences (for example: mutation or selection).
In order for Hardy-Weinberg Equilibrium equation to apply some basic
assumptions about the population are made.
As you can see, these conditions rarely apply in most wild populations.
Rather, it describes the behaviour of an ideal population. Nevertheless,
it can be used to gather information about genotype frequencies within
populations. The formula to calculate Hardy-Weinberg Equilibrium for two
alleles is:
p²+ 2pq + q² = 1
In this case, p² is the frequency of the
dominant homozygmous genotype (AA) , 2pq is the frequency
of the heterozygous genotype frequency (Aa) and q² is the
frequency of the recessive homozygous genotype (aa). The
relationship is demonstrated in Figure 1.
Question
Cystic Fibrosis (CF) is an inherited disorder which occurs when
individuals are born with two recessive alleles (aa)
(For more information of Cystic Fibrosis click here.)
The frequency of CF (aa) in European populations is estimated at 1/2500
Using the equation above and the assumption that p + q = 1, calculate the
number of carriers (Aa) in Europe.